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Average force between an object and non-movable object?

  1. Nov 30, 2009 #1
    1. The problem statement, all variables and given/known data

    A golf ball of mass 41.8 g is dropped from a height h = 1.41 m onto a hard floor and bounces back to exactly that same height. What is the average force (in N) on the ball during the 0.012 s that it was in contact with the floor?

    2. Relevant equations

    Impulse = Ft
    Impulse = m(Vf - Vi)

    3. The attempt at a solution
    I am not quite sure how to proceed with this problem, becuase I am completely clueless as to how I should go about calculating the change in velocity, becuase if the ball returns to the same height, (no friction of air resistance) then arent the Vi and Vf both = 0?
     
  2. jcsd
  3. Nov 30, 2009 #2

    tiny-tim

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    Hi sirfinklstin! :smile:
    Yes, but you want the two velocities at ground level. :wink:
     
  4. Nov 30, 2009 #3
    How would the velocities be calculated? 0 + (9.8 m/s)(1.41m)?
     
  5. Nov 30, 2009 #4

    tiny-tim

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    what? v = as ?? :confused:
     
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