Average force exerted by the ball

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Homework Help Overview

The problem involves a baseball caught by a fielder's glove, requiring the calculation of the average force exerted by the ball during the catch. The context includes concepts from mechanics, specifically relating to kinetic energy and forces.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between kinetic energy and force, with some suggesting the use of energy methods and others questioning the appropriate equations for calculating force. There are attempts to derive acceleration using kinematic equations based on the change in velocity and distance.

Discussion Status

The discussion is active, with participants providing guidance on the use of kinematic equations and clarifying the relationship between force, mass, and acceleration. Multiple approaches are being explored, and there is a focus on ensuring correct calculations and unit considerations.

Contextual Notes

Participants note the importance of unit consistency and the implications of negative signs in calculations. There is an emphasis on understanding the underlying physics rather than just arriving at a numerical answer.

mathcrzy
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Homework Statement



A baseball (m = 145 g) traveling 35 m/s moves a fielder's glove backward 15 cm when the ball is caught. What was the average force exerted by the ball on the glove?
Magnitude

Homework Equations



-(1/2)mv^2

The Attempt at a Solution



(1/2)(145)(35)^2=-88812.5
 
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you have calculated the kinetic energy lost. The problem asks for the force. What equation(s) might you use to solve for F?
 
F=(1/2)kx^2
 
Be careful with your calculations - baseball m = 145 g ...
 
mathcrzy said:
F=(1/2)kx^2
No, you're fishing in the wrong pool! Are you familiar with energy methods, or kinematics and Newton 2?
 
would the equation just be F=mv?
 
mathcrzy said:
would the equation just be F=mv?
You mean F=ma, don't you? So how would you calculate 'a' knowing that the ball goes from 35m/s to a stop in a 15cm distance? (Hint: use the kinematic equation that relates distance with acceleration and velocity change, and watch your units.
 
Vf^2=Vi^2*a*d
 
0=1225+2*a*.15
-2*a*.15=1225
a*.15=-612
a=-4083.3
 
  • #10
mathcrzy said:
0=1225+2*a*.15
-2*a*.15=1225
a*.15=-612
a=-4083.3
Yes that looks good, don't forget units of a is m/sec^2. What does the minus sign tell you? Now plug it into F=ma to solve for F, watch units, and interpert the significance of the minus sign.
 

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