(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Two bodies A and B collide in a totally inelastic collision. Using the relevant equations and given that the mass of body A is 1200kg and the collision lasts for 0.2s, determine the average force vectors acting on each body during the collision.

2. Relevant equations

v_{A}=5i+3j m/s

v_{B}=-i+4j m/s

m_{A}=(3/2)m_{B}

Common velocity after collision v=2.6i+3.4j m/s

3. The attempt at a solution

attempt 1

Ft = (m_{A}+m_{B})v - (m_{A}v_{A}+m_{B}v_{B})

calculation checked and rechecked... leads to wrong answer

attempt 2

Ft = (m_{A}+m_{B})v - (m_{A}v_{A}-m_{B}v_{B})

calculation checked and rechecked... leads to wrong answer

attempt 3

F_{A}t=0.5(m_{A}+m_{B})v - m_{A}v_{A}

F_{B}t=0.5(m_{A}+m_{B})v - m_{B}v_{B}

calculation checked and rechecked... leads to wrong answer

Answer is stated as "F_{A}= -F_{B}= (-14400i+2400j) N in the mark scheme

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# Homework Help: Average force in totally inelastic collision

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