Average height of molecules in a box as a function of temperature

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Homework Help Overview

The problem involves a circular cylinder filled with monatomic gas molecules at a given temperature, exploring how the average height of these molecules varies with temperature under the influence of gravity. The context includes the application of the Boltzmann distribution to determine the average height as a function of temperature.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the derivation of the average height formula and the application of limits as temperature approaches zero and infinity. There is mention of using l'Hôpital's rule and expanding exponentials to analyze the behavior of the function.

Discussion Status

The discussion includes attempts to derive the average height expression and explore its limits. Some participants have provided guidance on the mathematical techniques needed to evaluate the limits, while others express uncertainty about achieving the correct results for the limits at both extremes of temperature.

Contextual Notes

Participants are navigating through the complexities of the mathematical expressions involved and the implications of the limits on the average height of gas molecules. There is an acknowledgment of the challenges posed by the exponential terms in the equations.

Kilian Stenning
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Homework Statement


A circular cylinder of height H is filled with monatomic gas molecules at temperature T. The cylinder stands on the surface of the Earth so that the gas molecules are subject to the gravitational field g.

(a) Find the average height, z , of the molecules in the cylinder as a function of temperature. (Hint: The probability of finding a molecule at height z is governed by the Boltzmann distribution). Show that for

T → 0, z = 0 , and for T → ∞ , z = H/2 .

Homework Equations


f(z) = Cexp(-mgh/kt)
<z> =∫ z fz dz/∫ fz dz

The Attempt at a Solution


let B=mg/kT
Ive got an answer for <z> to be (1/B)*(1-(e^(-BH))*(BH+1))/(1-e^(-BH))
To get the limits I've tried to use l'hospital's rule w.r.t T but I can't seem to get the right answer
 
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Hello Kilian, :welcome:

The brackets tend to make it hard to read. $$
(1/B)\ * \ (1\ \ -\ \ (\exp(-BH))*(BH+1)\ \ \ )\ \quad /\quad (1-\exp (-BH))
$$Do I see $$ <Z> \ = {kT\over mg} \ \
{ 1 - \left ({mgh\over kT}+1\right ) e^{-{mgh\over kT}} \over
1 - e^{-{mgh\over kT} }} \quad ?$$
In which case I see the ##T\rightarrow 0## limit, but not the other one !
 
For the T → ∞ case, you will need to use l'Hopital's rule twice. Or you can expand the exponentials to second order in BH = mgH/(kT).
 
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thanks got it now!
 

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