RMS velocity of molecules in a mixture

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Homework Help Overview

The discussion revolves around the calculation of the root mean square (RMS) velocity of molecules in a mixture of gases, specifically focusing on the relationship between the RMS velocities of individual gases and the mixture. The context includes concepts from kinetic theory and thermodynamics.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore the relationship between the RMS velocities of individual gases and the mixture, questioning the validity of the original equations presented. There is a discussion on whether to sum the average kinetic energies or consider the average of the averages. Additionally, participants investigate how to calculate the RMS velocity of a mixture based on the individual velocities.

Discussion Status

The discussion is active, with participants questioning assumptions and clarifying the relationships between the variables involved. Some guidance has been offered regarding the calculation of RMS velocities, but no consensus has been reached on the final approach to find the RMS velocity of the mixture.

Contextual Notes

There are indications of potential misunderstandings regarding the equations used and the assumptions about temperature and mass in the context of the gases being mixed. Participants are also navigating the implications of their calculations and definitions.

Saptarshi Sarkar
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Homework Statement
A vessel at temperature T contains equal number of molecules of two gases whose masses are m and 4m respectively. What is the RMS velocity of molecules in the mixture?
Relevant Equations
##v_{rms} = \frac {\sqrt {3k_bT}} m##
I know that for a single monoatomic gas with RMS velocity ##v_{rms}## , $$\frac 1 2mv_{rms}^2 = \frac 3 2k_bT$$ where ##m## is mass of a single molecule, ##k_b## is Boltzmann constant and ##T## is temperature of the gas.

For a mixture of gas, I know that the average kinetic energy after mixing the gases will be equal to the sum of average kinetic energy of the two constituent gases before mixing.

##\frac 1 2mv_{rms_1}^2 + \frac 1 24mv_{rms_2}^2 = \frac 1 25mv_{rms}^2##

But, I have no idea how to use this to find the RMS velocity of the mix.
 
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Saptarshi Sarkar said:
the average kinetic energy after mixing the gases will be equal to the sum of average kinetic energy of the two constituent gases before mixing.
I don’t think you mean that.
It might be the average of the averages, which fits better with the equation you wrote, but not the sum.
What does your first equation tell you about the relationship between the two individual rms speeds?
 
haruspex said:
I don’t think you mean that.
It might be the average of the averages, which fits better with the equation you wrote, but not the sum.
What does your first equation tell you about the relationship between the two individual rms speeds?

I did a mistake and wrote the formula wrong, it should be ##v_{rms} = \sqrt \frac {3k_bT} m##

From this I can say that if the absolute temperature of the two gases be equal, then ##\frac {v_{rms_1}} {v_{rms_2}} = \sqrt \frac {4m} m = 2##
 
Saptarshi Sarkar said:
I did a mistake and wrote the formula wrong, it should be ##v_{rms} = \sqrt \frac {3k_bT} m##

From this I can say that if the absolute temperature of the two gases be equal, then ##\frac {v_{rms_1}} {v_{rms_2}} = \sqrt \frac {4m} m = 2##
Right, so consider one molecule of each. What is the RMS speed of the pair?
 
haruspex said:
Right, so consider one molecule of each. What is the RMS speed of the pair?

Should it be ##\frac 3 2v_{rms_1}##?
 
Saptarshi Sarkar said:
Should it be ##\frac 3 2v_{rms_1}##?
How do you find the RMS of two numbers?
 
haruspex said:
How do you find the RMS of two numbers?

By taking the root of the average of the square. So, will it be ##\sqrt \frac {5v_{rms_1}^2} 2##?
 
Saptarshi Sarkar said:
By taking the root of the average of the square. So, will it be ##\sqrt \frac {5v_{rms_1}^2} 2##?
Yes.
 
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