Average Pressure Radiation on Perfectly Absorbing Surface

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SUMMARY

The discussion centers on calculating the average pressure exerted by a sinusoidal electromagnetic wave on a perfectly absorbing surface located at a distance R from the source. The average pressure on a perfectly reflecting surface is given by the formula (2 * Intensity) / (speed of light), while for a perfectly absorbing surface, it is (Intensity) / (speed of light). The confusion arises from the differing results of 1/8 and 1/4, attributed to the distance factor being squared and the absorption factor of 1/2. The correct average pressure on the absorbing surface at double the distance is definitively 1/8.

PREREQUISITES
  • Understanding of electromagnetic wave properties
  • Familiarity with pressure radiation concepts
  • Knowledge of intensity calculations in physics
  • Basic grasp of spherical surface area calculations
NEXT STEPS
  • Study the derivation of pressure radiation formulas for absorbing and reflecting surfaces
  • Explore the relationship between intensity and distance in electromagnetic waves
  • Learn about the implications of surface properties on radiation pressure
  • Investigate similar problems in "University Physics with Modern Physics" by Sears and Zemansky
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This discussion is beneficial for physics students, educators, and professionals interested in electromagnetic theory, particularly those focusing on radiation pressure and surface interactions.

rugerts
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Homework Statement


A light source radiates a sinusoidal electromagnetic wave uniformly in all directions. This wave exerts an average pressure p on a perfectly reflecting surface a distance R away from it. What average pressure (in terms of p) would this wave exert on a perfectly absorbing surface that was twice as far from the source?

Homework Equations


pressure radiation of perfect absorber = (Intensity)/(speed of light)

pressure radiation of perfect reflector = (2 * Intensity)/(speed of light)

Intensity = (Power)/(Area)

Surface Area of Sphere = 4*pi*R^2

The Attempt at a Solution


IMG_1143.v2.jpg

Since you probably can't see that, here's an imgur link: https://imgur.com/a/uxltWGV

When I try to do the math, I get that it's a factor of 1/8. But, if I try to reason through it, it seems like 1/4 is a reasonable answer since I'm just doubling a square factor.

Thanks for your time.
 

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rugerts said:
since I'm just doubling a square factor.
You are doubling the distance factor, which is squared, but you are also getting afactor of 1/2 from the absorption. Where's the puzzle?
 
haruspex said:
You are doubling the distance factor, which is squared, but you are also getting afactor of 1/2 from the absorption. Where's the puzzle?
The puzzle is that I get an answer of 1/8 and an answer I found online is 1/4.
 
rugerts said:
The puzzle is that I get an answer of 1/8 and an answer I found online is 1/4.
Please post the link.
 
haruspex said:
Please post the link.

http://www.slader.com/textbook/9780321696861-sears-and-zemanskys-university-physics-with-modern-physics-13th-edition/1074/discussion-questions/12/
 
haruspex said:
Please post the link.
?
 
rugerts said:
http://www.slader.com/textbook/9780321696861-sears-and-zemanskys-university-physics-with-modern-physics-13th-edition/1074/discussion-questions/12/
The question discussed at that link considers two perfectly reflecting surfaces. The question in post #1 of this thread compares a reflecting surface with an absorbing one.
 
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