Average value of f(x,y) = xy in quarter circle x^2 + y^2 < 1 in Q1.

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SUMMARY

The average value of the function f(x, y) = xy over the quarter circle defined by x² + y² ≤ 1 in the first quadrant is calculated using the formula for average value, which is (1/Area of R) ∫∫_R f(x, y) dA. The area of the quarter circle is confirmed to be π/4. The average value is derived as (4/π) ∫₀^(π/2) ∫₀¹ (r cos θ)(r sin θ) r dr dθ, resulting in an average value of 1/(2π). The use of polar coordinates and the Jacobian is correctly applied in this calculation.

PREREQUISITES
  • Understanding of polar coordinates and their application in double integrals
  • Knowledge of calculating areas of geometric shapes, specifically circles
  • Familiarity with the concept of average value of a function over a region
  • Basic calculus skills, including integration techniques
NEXT STEPS
  • Study the application of Jacobians in changing variables in multiple integrals
  • Explore advanced integration techniques in polar coordinates
  • Learn about the properties of average values in different geometric contexts
  • Investigate the implications of integrating functions over non-standard regions
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Students and educators in calculus, particularly those focusing on integration techniques and applications in polar coordinates, as well as anyone seeking to improve their problem-solving skills in mathematical analysis.

VinnyCee
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Here is the problem:

Find the average value of f\left(x, y\right) = x\;y for the quarter circle x^2 + y^2 \le 1 in the first quadrant.

Here is what I have:

Average value equation is \frac{1}{Area\;of\;R} \iint_{R} f\left(x, y\right) dA

f\left(x, y\right) = x\;y = \left(r\;\cos\theta\right)\left(r\;\sin\theta\right)

The area of one quarter of a unti circle is \frac{\pi}{4}, right?

Average = \frac{4}{\pi}\;\int_{0}^{\frac{\pi}{2}}\int_{0}^{1}\;\left(r\;\cos\theta\right)\left(r\;\sin\theta\right)\;r\;dr\;d\theta = \frac{1}{2\pi}

Is this correct?
 
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Absolutely, and good job remembering the jacobian in polar coordinates.
 
Thank you

Many thanks. I will probably be checking a few others before I am through.

I wonder if I should make a thread for "Check my Calculus Answers Please" and put them all in there or something? On the other hand, I think that individually posting each problem gets quicker results and is easier to search (i guess).
 
In order to get useful feedback and responses, it's best to title your threads appropriately--- putting something like "check my work..." generally isn't too appealing, so you're probably right--- that is, make threads that are individual for a specific problem, with the statement and reasoning placed in the first post.

You have been doing this but just so others know!
 

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