Average velocity and average speed problem.

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SUMMARY

The discussion centers on a physics problem involving three individuals moving towards a door at a speed of 3.50 m/s, each with a depth of 0.25 m and separated by a distance of 1.75 m. The key questions are to determine the average rate at which the layer of people at the door increases and the time it takes for the layer's depth to reach 5.0 m. The problem highlights the potential dangers of crowding in emergency situations, emphasizing the need for clear calculations and understanding of movement dynamics.

PREREQUISITES
  • Understanding of basic kinematics, including velocity and acceleration.
  • Familiarity with the concept of average rate of change in physics.
  • Knowledge of spatial arrangement and distance measurement in motion problems.
  • Ability to interpret and analyze graphical representations of motion.
NEXT STEPS
  • Calculate the average rate of increase of the layer of people using the formula for average velocity.
  • Determine the time required for the layer's depth to reach 5.0 m based on the given parameters.
  • Explore crowd dynamics and safety measures in emergency evacuations.
  • Review related physics problems involving motion and crowd behavior for deeper understanding.
USEFUL FOR

Students studying physics, educators teaching kinematics, safety professionals analyzing crowd behavior, and anyone interested in emergency management scenarios.

afcwestwarrior
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Homework Statement


The people move toward the door at a speed V s=3.50m/s,are each d=.25m in depth, and are separated by L=1.75 m. The arrangement in Fig.2=22 occurs at time t=0(a) at what average rate does the layer of people at the door increase? (b) at what time does the layer's depth reach 5.0m? (the answers reveal how quickly such a situation becomes dangerous.
In the picture there are 3 people running towards a door


v= change in x/ change in t
 
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afcwestwarrior said:

Homework Statement


The people move toward the door at a speed V s=3.50m/s,are each d=.25m in depth, and are separated by L=1.75 m. The arrangement in Fig.2=22 occurs at time t=0(a) at what average rate does the layer of people at the door increase? (b) at what time does the layer's depth reach 5.0m? (the answers reveal how quickly such a situation becomes dangerous.
In the picture there are 3 people running towards a door


v= change in x/ change in t

Hi afcwestwarrior! :smile:

I suspect everyone's as confused as I am …

are the 3 people running side-by-side or front-to-back?

where is everyone else?
 

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