Average Velocity for Three People's Trips

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SUMMARY

The average velocity for three individuals traveling at different speeds—Person A at 10.2 m/s, Person B at 10.4 m/s, and Person C at 3.51 m/s—was incorrectly calculated by simply averaging their speeds, resulting in 8.0 m/s. The correct method involves calculating the total displacement and total time for each individual, leading to an average velocity of 4.89 m/s as stated in the textbook. The discussion highlights the importance of understanding the context of the velocities, specifically whether the individuals traveled for identical times or distances.

PREREQUISITES
  • Understanding of average velocity calculations
  • Familiarity with displacement and time concepts
  • Knowledge of root mean square (RMS) calculations
  • Basic principles of kinematics
NEXT STEPS
  • Research how to calculate average velocity using total displacement and total time
  • Learn about root mean square velocity and its applications
  • Study kinematic equations for motion in one direction
  • Explore the implications of different travel times and distances on average velocity
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Students studying physics, educators teaching kinematics, and anyone interested in understanding velocity calculations in real-world scenarios.

Balsam
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Person A travels 10.2m/s[forward]. Person B travels 10.4m/s[forward]. Person C travels 3.51m/s[forward]. Find the average velocity for the trio.I added all 3 velocities(just the magnitudes) and divided by 3, but my answer was different from the textbook's. I got 8.0m/s[forward], but the answer in the book is 4.89m/s[forward]. I don't know what I did wrong.
 
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Balsam said:
Person A travels 10.2m/s[forward]. Person B travels 10.4m/s[forward]. Person C travels 3.51m/s[forward]. Find the average velocity for the trio.I added all 3 velocities(just the magnitudes) and divided by 3, but my answer was different from the textbook's. I got 8.0m/s[forward], but the answer in the book is 4.89m/s[forward]. I don't know what I did wrong.
Please remember to use the Homework Help Template when posting here in the schoolwork forums. Thank you.

Now, please show your detailed calculations so we can look for any errors. :smile:
 
berkeman said:
Please remember to use the Homework Help Template when posting here in the schoolwork forums. Thank you.

Now, please show your detailed calculations so we can look for any errors. :smile:

10.2+10.4+3.51=24.11--> 24.11/3= ~8.0m. <-- That is what I did
 
Balsam said:
10.2+10.4+3.51=24.11--> 24.11/3= ~8.0m. <-- That is what I did
Your work looks correct. Are you sure you copied the problem statement correctly? Are you sure they all were moving in the same direction (forward)? Are they all facing the same direction as they move?
 
berkeman said:
Your work looks correct. Are you sure you copied the problem statement correctly? Are you sure they all were moving in the same direction (forward)? Are they all facing the same direction as they move?
Yes, I'm sure. All of the individual velocity values are given in the textbook, I copied them correctly.
 
Balsam said:
Yes, I'm sure. All of the individual velocity values are given in the textbook, I copied them correctly.
Is there a figure that goes with the question? Can you upload a picture of the question?
 
Balsam said:
Person A travels 10.2m/s[forward]. Person B travels 10.4m/s[forward]. Person C travels 3.51m/s[forward]. Find the average velocity for the trio.
Are these traveling for identical times OR for identical distances?

Example: 3 friends in a car take turns at driving ...

EDIT: either way, still can't get the book's answer though
 
NascentOxygen said:
Are these traveling for identical times, or over identical distances?

Example: 3 friends in a car take turns at driving ...

EDIT: either way, still can't get the book's answer though
Try root mean square. Ans comes close.
That could be the method.
 
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NascentOxygen said:
Are these traveling for identical times OR for identical distances?

Example: 3 friends in a car take turns at driving ...

EDIT: either way, still can't get the book's answer though
I figured it out-- you have to add all of their displacements to get the total displacement, then add all of their times to get the total time, and then divide those 2 numbers to get their average velocity.
 
  • #10
Balsam said:
I figured it out-- you have to add all of their displacements to get the total displacement, then add all of their times to get the total time, and then divide those 2 numbers to get their average velocity.
Does that get you to the book's answer?
 
  • #11
256bits said:
Try root mean square. Ans comes close.
That could be the method.
Interesting...but on what basis could you justify RMS?
 
  • #12
NascentOxygen said:
Does that get you to the book's answer?
Yeah, it does.
 
  • #13
Balsam said:
Yeah, it does.
Using your method I don't get the textbook's answer.
 
  • #14
NascentOxygen said:
Interesting...but on what basis could you justify RMS?
RMS doesn't give the book answer either I believe, but I was considering a velocity distribution ( 3 points ?? ).
Is that valid for velocities in one direction - I can's say.
The answer seems to be weighted towards the slower individual though.
 

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