- #1

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## Homework Statement

A person riding a bike travels at an

__average velocity of 3m/s for 30min__. The person then takes a water

__break for 15 min__. The person finally travels a

__distance of 450m__at an average velocity of 1.5m/s. What is the persons

__average velocity?__

2. Homework Equations

[/B]

**Average Velocity: Δx/Δt**

**(Change in positions vs change in time)**

**Conversion**

**I first labeled the data.**

3. The Attempt at a Solution

1.

3. The Attempt at a Solution

1.

__Trip1__Average Velocity1: 3m/s

for

Time: 30min= 1800s

**Break**Time: 15min= 900s

__Trip2__Average Velocity2: 1.5m/s

for

Distance: 450m

**I drew a picture next of what that would look like**

2.

2.

**3.**Next, I converted the minutes of the first trip and the break taken into seconds

**4.**I'm assuming that the equation for average velocity must be used in order to solve this.

So here is where I get stuck. I thought of adding the velocities for a total but then thought against it. I then thought to solve for the time in trip two then the distance in trip one.

- Trip2:
**T=D/T**Time=300s - Trip1:
**D=V⋅T**Distance= 5400m