A person riding a bike travels at an average velocity of 3m/s for 30min. The person then takes a water break for 15 min. The person finally travels a distance of 450m at an average velocity of 1.5m/s. What is the persons average velocity?
2. Homework Equations
- Average Velocity: Δx/Δt
3. The Attempt at a Solution
1. I first labeled the data.
Average Velocity1: 3m/s
Time: 30min= 1800s
Time: 15min= 900s
Average Velocity2: 1.5m/s
2. I drew a picture next of what that would look like
3. Next, I converted the minutes of the first trip and the break taken into seconds
4. I'm assuming that the equation for average velocity must be used in order to solve this.
So here is where I get stuck. I thought of adding the velocities for a total but then thought against it. I then thought to solve for the time in trip two then the distance in trip one.
- Trip2: T=D/T Time=300s
- Trip1: D=V⋅T Distance= 5400m