Average Velocity on a Position vs Time Graph

[mandy9008]

A graph of position versus time for a certain particle moving along the x-axis is shown in the figure below. Find the average velocity in the following time intervals. (The horizontal axis is marked in increments of 1 s and the vertical axis is marked in increments of 2 m.)



avg velocity = change in x / change in y



a. v= 2/10 = 0.2
b. v= 4/5 - 0.8
c. v= 2/0 = 0
d. v= 3/10 = 0.3
e. v= 8/5 = 1.6

 

[inky]

A graph of position versus time for a certain particle moving along the x-axis is shown in the figure below. Find the average velocity in the following time intervals. (The horizontal axis is marked in increments of 1 s and the vertical axis is marked in increments of 2 m.)



I think your calculation is in correct. For example ,
between 0 to 2s, particle is moving with constant acceleration. So you should use
v(bar)=(u+v)/2=(10+0)/2=5ms-1

 

[inky]

I am sorry. I thought velocity-time graph. It is displacement- time graph. For displace-time graph,

average velocity=(x2-x1)/(t2-t1)

For example ,
0 to 2s,
average velocity=10/2=5 ms-1
2 to 4s
average velocity=(10-5)/2= 2.5 ms-1
4 to 5s
average velocity=0
5 to 7s
average velocity=5 ms-1
7 to 8s
average velocity=10/2=5 ms-1