Average Velocity over intervals

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Homework Help Overview

The discussion revolves around calculating the average velocity of an arrow shot upwards, described by a height function h=50t-0.36t^2, over a specific time interval [1, 1.03] seconds.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the method for finding average velocity, with one suggesting the use of secant lines to determine the average rate of change between two points on the height function.

Discussion Status

The conversation includes confirmation of understanding regarding the problem's nature, with some participants clarifying the distinction between average rate of change and average value of the function.

Contextual Notes

There is an indication of uncertainty regarding the correct interpretation of the average velocity calculation, as well as the potential confusion between different mathematical concepts related to the problem.

step1536
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An arrow is shoot up in the air at 50m/s. Its height in meters after t sec. is h=50t-0.36t^2. Find the average velocity over interval [1,1.03], four decimal places.
 
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step1536 said:

Homework Equations


this may help (if I remember it correctly)

[tex]F(x)_{average}=\frac{1}{b-a} \int_{a} ^{b} f(x) dx[/tex]
 
I think this is a simple secant problem where you find the average rate of change between the two points (1, h(1)) and (1.03, h(1.03)) and not the average value of the function.
 
Thanks a lot. I knew that but I wanted to make sure.
 

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