Avg. temperature rise & energy conversion

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SUMMARY

The discussion centers on calculating the average temperature rise of a pond due to solar energy and determining the mass conversion rate of the sun into energy. The energy flux from the sun is established at 1.4 kilowatts per square meter, which translates to 1400 joules per second per square meter. For a pond with an area of 100 square meters and a depth of 0.1 meters, the average temperature rise after 1000 seconds can be calculated using the formula for energy transfer. Additionally, the mass-energy equivalence principle (E=mc²) is utilized to find the sun's mass conversion rate.

PREREQUISITES
  • Understanding of energy flux and its calculation
  • Familiarity with the concept of mass-energy equivalence (E=mc²)
  • Basic knowledge of thermodynamics and heat transfer
  • Ability to perform unit conversions, particularly between watts and joules
NEXT STEPS
  • Calculate the average temperature rise of the pond using the formula Q=mcΔT
  • Explore the implications of solar energy flux on climate change
  • Investigate the sun's mass loss rate using E=mc² in detail
  • Learn about energy transfer in fluids and its applications in environmental science
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Students and professionals in physics, environmental science, and renewable energy sectors who are interested in understanding energy transfer processes and solar energy applications.

timothy997
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The problem is: The sun is 1.5x10^11 meters from the earth. Energy from the sun is received at the Earth's surface at the rate of 1.4 kilowatts per square meter. I'm trying to find two answers:
1. This energy flux from the Sun falls on a pond of water 100 square meters in area and 0.1 meter in depth. Assume all of this energy heats the water. Find the average temp. rise of the pond after 10^3 seconds
2. Determine the rate in kilograms per second at which the sun's mass is being converted to energy.





For 1, energy flux is Iota=power/area, power=work/time,
For 2, the SA of a sphere is 4pir^2, E=mc^2



So far I have p/1000 for energy flux and power=w/1000. I'm stuck on what to do next, but since the question gives you the distance between the Earth and sun, would w=fd help you find the solution? This question seems unusual compared to ones I've done in the past.
 
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definition of a kilowatt

Remember that a kilowatt is 1000 watts, which is 1000 joules/second.

Hence, the flux is (1400 joules/second)/100 meters squared, which is 140 joules per meter squared second.

I am not so sure about the rest of the problem, but perhaps this information will help you. I will keep looking at it, though.
 

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