MHB B20.<= to the length of the dividend

  • Thread starter Thread starter karush
  • Start date Start date
  • Tags Tags
    Length
karush
Gold Member
MHB
Messages
3,240
Reaction score
5
Screenshot 2021-12-11 12.17.59 PM.png

Do the division using the c-strips to make a train of as many of the divisor as possible such that the length of the train you make is less than or equal to the length of the dividend, and if you were to add one more of the divisor to the train, it would be longer than the dividend.
If the train ends up being the same length as the dividend, there will be no remainder and the second blank will be empty.
a. Make a diagram using c-strips.
b. In terms of the strips $B+P=\boxed{?}$ reminder $\boxed{?}$ since $B=\cdot P+\boxed{?}$
c. In terms of the numbers $\boxed{?}/ \boxed{?}=\boxed{?}$ remainder $ \boxed{?} $ since $\boxed{?}=\boxed{?} \cdot \boxed{?}$

sorry I just think the way this was written was ? just a simple division problem with a remainder
 

Attachments

  • Screenshot 2021-12-11 12.17.59 PM.png
    Screenshot 2021-12-11 12.17.59 PM.png
    46.6 KB · Views: 109
Mathematics news on Phys.org
Is this a "Math for Elementary School Teachers" class? It looks like the way one would introduce division in an elementary class. To demonstrate "6/2" one could take a strip of paper 6" long and 3 strips 2" and line the 2" strips along side the 6" strip.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
I'm interested to know whether the equation $$1 = 2 - \frac{1}{2 - \frac{1}{2 - \cdots}}$$ is true or not. It can be shown easily that if the continued fraction converges, it cannot converge to anything else than 1. It seems that if the continued fraction converges, the convergence is very slow. The apparent slowness of the convergence makes it difficult to estimate the presence of true convergence numerically. At the moment I don't know whether this converges or not.
Back
Top