Back to Simple Algebra: Solve 76.262 Equation

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Discussion Overview

The discussion revolves around solving an algebraic equation involving a denominator of 900. Participants explore methods for eliminating the denominator and express confusion regarding the presence of another denominator, 1000, in the context of the equation.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant initially seeks guidance on how to eliminate the denominator of 900 in the equation 76.262 = ((124 + 30b - c)/900) + c.
  • Another participant suggests that multiplying every term by 900 would effectively eliminate the denominator.
  • A claim is made about the presence of a denominator of 1000, which is contested by another participant who questions its relevance.
  • One participant acknowledges that focusing on the decimal part of the equation is unnecessary for solving the problem unless a specific application requires it.

Areas of Agreement / Disagreement

There is disagreement regarding the presence and relevance of the denominator of 1000. While some participants agree on the method of multiplying by 900 to eliminate the denominator, the discussion does not reach a consensus on the necessity of considering the decimal component.

Contextual Notes

Participants express varying levels of familiarity with algebra, and there are references to previous knowledge and confusion about the equation's structure. The discussion includes assumptions about the relevance of certain terms in the equation.

simpComp
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Hello,

Okay, after doing perhaps 1 hour of math a year for 20 years, I realize I forgot a lot!

Can someone please tell what I need to do if I want to get rid of the denominator of 900 in the following expression:

76.262 = ((124 + 30b - c)/900) + c

Please see attachment to see exact equation...

I am trying to find a number I can multiply 124 so that the result can be divided by 900... but I can seem to find it?

Thanks
 

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nevermind ... digging up my old algebra notes, I figured that I can multiply every term by 900...

jeeeezzze,,,
 
The denominators shown in the equation are 1000 and 900. See the "76.262". The common factor is 233253
 
In all due respect, where do you see 1000 as a denominator?
 
To get rid of the 900 we could
simply multiply all terms by 900...no?

(900)76.262 =
((900*124 + 900*30b - 900*c)/900) + 900*c

this works!
thanks
 
simpComp said:
In all due respect, where do you see 1000 as a denominator?

Already explained in my post. It is correct, but unnecessary if you wish to maintain decimalized result.
 
simpComp said:
Hello,

Okay, after doing perhaps 1 hour of math a year for 20 years, I realize I forgot a lot!

Can someone please tell what I need to do if I want to get rid of the denominator of 900 in the following expression:

76.262 = ((124 + 30b - c)/900) + c

Please see attachment to see exact equation...

I am trying to find a number I can multiply 124 so that the result can be divided by 900... but I can seem to find it?

Thanks

Now that I look at the equation again, my picking at the decimal part, ".262" with denominator of 1000 plays no part in the solution. Changing the form would not be useful unless a specific application depended on it.
 
thanks for your help...
it is most appreciated !
 

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