(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A 900 kg car goes up along an inclined road by 30 degrees characterized by an acceleration of 0.25 m/s^2. If friction coefficient is 0.5, find the magnitude of the force that moves the car.

Solution: F = 12285.6 N

2. Relevant equations

3. The attempt at a solution

http://img259.imageshack.us/img259/5361/imagetcq.jpg [Broken]

Sum of all forces is: m *a = 900 * 0.25 = 225

Then Ffriction is = 0.5 * FwPerpendicular = 0.5 * sin(60) * 900 * 9.8 = 3819 N

Then Fwparallel is = sin(60) * 900 * 9.8 = 4410

F = 3819 + 4410 + 225 = 8454 N != solution

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Balance of a car on an inclined plane

**Physics Forums | Science Articles, Homework Help, Discussion**