Balanced Y-connected 3-phase load

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SUMMARY

A balanced 3-phase supply with a voltage of VRMS = 6599.1V is applied to a Y-connected load with identical impedances of Z = 50<37°. The calculated phase voltages are Van = 3810<0, Vbn = 3810<-120, and Vcn = 3810<-240. The phase currents are Ian = 76.2<-37, Ibn = 76.2<-157, and Icn = 76.2<-277. The total active power supplied to the load is 695490W, and the total reactive power is 524090VAR, confirmed through the equations P=√3VLIcosΦ and Q=√3VLIsinΦ with Φ=37°.

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Homework Statement


A balanced 3 phase supply of VRMS = 6599.1V is applied to a balanced Y-connected 3-phase load consisting of three identical impedances Z = 50<37°. Take the phase-to-neutral voltage Van as the reference. Calculate:

A)Phase voltages Van, Vbn, Vcn
B)Phase currents Ian, Ibn, Icn
C)Total active and reactive power supplied to load
upload_2016-10-26_20-26-45.png

Homework Equations


upload_2016-10-24_23-23-24-png.107967.png


The Attempt at a Solution


A)
6599.1V/sqrt(3) = 3810
Van = 3810<0
Vbn = 3810<-120
Vcn = 3810<-240

B)

Ian = 3810<0/50<37° = 76.2<-37
Ibn = 76.2<-157
Icn = 76.2<-277

Did I do parts A and B correctly?
 
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eehelp150 said:

Homework Statement


A balanced 3 phase supply of VRMS = 6599.1V is applied to a balanced Y-connected 3-phase load consisting of three identical impedances Z = 50<37°. Take the phase-to-neutral voltage Van as the reference. Calculate:

A)Phase voltages Van, Vbn, Vcn
B)Phase currents Ian, Ibn, Icn
C)Total active and reactive power supplied to load
View attachment 108042

Homework Equations


upload_2016-10-24_23-23-24-png.107967.png


The Attempt at a Solution


A)
6599.1V/sqrt(3) = 3810
Van = 3810<0
Vbn = 3810<-120
Vcn = 3810<-240

B)

Ian = 3810<0/50<37° = 76.2<-37
Ibn = 76.2<-157
Icn = 76.2<-277

Did I do parts A and B correctly?
Yes.
 
cnh1995 said:
Yes.
For total active power, I got:
695490W
For total reactive power, I got:
524090VAR
Would you mind double checking?
 
eehelp150 said:
For total active power, I got:
695490W
For total reactive power, I got:
524090VAR
Would you mind double checking?
I am getting values close to yours, just a difference of a few watts.
P=√3VLIcosΦ.
Q=√3VLIsinΦ.
Φ=37°.
 

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