- #1

CasterSkux

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I am a student doing a simple course in Electrical Engineering.

I've got an enquiry regarding this question

"

**1.**In a three phase 4 wire system with phase to neutral voltage of 230V, a balanced set of resistive loads of 8 ohms are connected between each phase and neutral.

If the fuse cartridge of phase

**“C”**blows, what will be the currents in the corresponding phases and the symmetrical components of the load currents?

""

We use a program to calculate the symmetric components. I believe I need to construct the resultant phasor of this system and derive the symmetric components

This is my approach:

1) Assume this is a star connected load, therefore the phase voltage is Vp = Vl / sqrt(3) = 230/sqrt(3) = 132.7906 V

2) Calculate the balanced current that flows through each resistor I = V/R, I = 132.7906V/8 = 16.5988.

3) If Phase C is eliminated from the fuse, I think that the line/phase voltages stay the same (as there is a neutral) and hence the current is the same.

4) Therefore Phase A is 16.5988 amps and so is Phase B. Phase B is offsetted by 120 degrees taking A as the relative point.

5) Phase C is 0 and it's on the 240 degree mark on the phasor diagram.I was wondering if this is all right in approach?