Balancing Equations: High School Chemistry | C2H6 + O2 = 2CO2 + 3H2O

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Discussion Overview

The discussion revolves around the balancing of chemical equations, specifically focusing on the role of oxygen in these equations. Participants explore the implications of balancing equations with odd and even numbers of oxygen atoms, the necessity of pairing oxygen in its diatomic form (O2), and the treatment of oxygen in various compounds.

Discussion Character

  • Debate/contested
  • Conceptual clarification
  • Technical explanation

Main Points Raised

  • One participant questions whether oxygen must always be paired in diatomic form (O2) and if having an odd number of oxygen atoms on both sides of a balanced equation is acceptable.
  • Another participant asserts that while O2 must be in pairs, it is acceptable to have an odd total number of oxygen atoms as long as they are correctly represented in the compounds on both sides.
  • Some participants suggest using fractional coefficients (e.g., 3½ O2) during the balancing process, but emphasize that the final equation should consist of the lowest integer coefficients.
  • There is a discussion about whether the requirement for oxygen to be paired applies to all compounds containing oxygen or just to gaseous oxygen (O2).
  • Participants clarify that compounds like H2O and MgO can exist with single oxygen atoms, indicating that the pairing rule does not apply to them.
  • Confusion arises regarding the book's statement about oxygen needing to be paired, with participants expressing differing interpretations of what "paired" means in the context of balancing equations.

Areas of Agreement / Disagreement

Participants express differing views on the necessity of pairing oxygen in balancing equations. While some agree that oxygen in its diatomic form must be treated as pairs, others argue that this does not apply to oxygen in compounds. The discussion remains unresolved regarding the implications of the book's statements on balancing equations.

Contextual Notes

There is uncertainty regarding the interpretation of "pairing" in the context of balancing equations, particularly whether it refers to the total number of oxygen atoms or only to the diatomic form of oxygen. The discussion also highlights the potential for confusion arising from the book's explanations.

Barclay
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This is a question, not a home work.

The book I'm reading explains how to balance equations step-by step.

UNBALANCED EQUATION IS THIS: C2H6 + O2 = CO2 + H2O

The book gets to this: C2H6 + O2 = 2CO2 + 3H2O

The book says "There are 7 oxygen on the right-hand-side but only 2 on the left". All fine so far.

Then the book says "Oxygen's HAVE to go around in PAIRS so how can you get an odd number (7) of them on the left side".

Then the book goes on to balance the equation: 2C2H6 + 7O2 = 4CO2 + 6H2OMy questions are this:

1. Do Oxygen's HAVE to go around in PAIRS? What if I balanced an equation (any equation) and there were say 7 oxygen on left side and 7 on the right side - would that be incorrect? Would I have to get 14 on both sides (or an even number on both sides)?

2. If the book is correct and "Oxygen's HAVE to go around in PAIRS" then what other elements HAVE to go around in pairs or triplets etc (for the purpose of balancing equations)?

[This is HIGH SCHOOL CHEMISTRY]

Thank you.
 
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Oxygen has to be paired as gas - it is perfectly fine to have 7 oxygen atoms at both sides, as long as some odd number is bound in molecules on both sides.
Your left side just has oxygen as O2, that cannot give an odd number.
Ozone is O3, but you will rarely see that in those questions.

then what other elements HAVE to go around in pairs or triplets etc (for the purpose of balancing equations)?
The typical gases apart from noble gases: hydrogen, nitrogen, oxygen, all halogens, and some more exotic gases.
 
To make balancing easier you can use something like 3\frac 1 2 O_2 to get 7 atoms of oxygen, but after the equation is balanced you should get rid of all fractional coefficients.

In other words: during balancing feel free to use fractions if it makes balancing easier, just remove them as the final step. Properly balanced equation should use a set of the lowest integer coefficients. Doesn't matter how you get there.
 
mfb said:
Oxygen has to be paired as gas - it is perfectly fine to have 7 oxygen atoms at both sides, as long as some odd number is bound in molecules on both sides.
Your left side just has oxygen as O2, that cannot give an odd number.

I'm not sure what the book means by "oxygen must be paired".

Does it mean there must be an EVEN number of oxygen atoms (in total) on each side of the equation?

PAIRED means an EVEN number yet MFB you say that 7 oxygen is okay on both sides.

Edited bit later:
I've just been looking at a few balanced equations and it seems that each compound that contains oxygen (in a balanced equation) must have an EVEN number of oxygen atoms on each individual molecule. Is that right?Why must oxygen be paired?
 
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Borek said:
To make balancing easier you can use something like 3\frac 1 2 O_2 to get 7 atoms of oxygen, but after the equation is balanced you should get rid of all fractional coefficients.

Yes the next step in the book does mention 3 1/2 fraction
 
Barclay said:
Does it mean there must be an EVEN number of oxygen atoms (in total) on each side of the equation?
No.
It just means you cannot have 1/2, 3/2 or similar fractions of O2 in the final equation.
 
mfb said:
No.
It just means you cannot have 1/2, 3/2 or similar fractions of O2 in the final equation.
Thanks for that BUT can there be single oxygens in the balanced equation?
E.g in the balanced equation:
Can there exist say H2O or does it have to be 2H2O ?
Can there exist say MgO or does it have to be 2MgO ?
 
Barclay said:
Can there exist say H2O or does it have to be 2H2O ?
Can there exist say MgO or does it have to be 2MgO ?

H2O and MgO are perfectly OK. Pure, gaseous oxygen is made of diatomic molecules, so it is O2. In other compounds it is no longer pure, gaseous oxygen, so it doesn't have to be in pairs.
 
Barclay said:
Thanks for that BUT can there be single oxygens in the balanced equation?
Yes.
Just forget the book's comment if it causes so much confusion. There is nothing special about oxygen.
 
  • #10
mfb said:
Just forget the book's comment if it causes so much confusion. There is nothing special about oxygen.

As I wrote earlier - the only way book can be confusing is when the comment about "single oxygens" is applied to every oxygen in every compound, and not only to gaseous, elemental oxygen O2.
 

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