1. The problem statement, all variables and given/known data Two rollers, of masses 2kg and 3kg, are connected over a pulley by a massless string. They rest in equilibrium on two inclined slopes, as shown in the diagram to the left. Friction is negligible. What is the distance X? 2. Relevant equations Fg = mg Component of Fg parallel to the slope = mgsin(theta) 3. The attempt at a solution Since they are in equilibrium, the forces on both sides must be equal. So I created a separate coordinate system for each side and found the forces acting along the slope. On the left side, the force of gravity parallel to the slope is (2kg)(10 m/s^2)(sin(theta)). To find theta, I did arctan(.3/.4) to get 36.87 degrees. So therefore (2kg)(10)(sin(36.87)) = 12 N. So the right side force must also be equal to 12 N. 12 N = (3kg)(10 m/s^2)(sin(theta)). So now I found this theta by solving the equation and got 23.58 degrees. And finally, to find x, I did sin(23.58) = 0.3/x --> x = 0.75 m. But the answer is 0.69 m. What did I do wrong?