Ball dropped through a tunnel through the earth.

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SUMMARY

The discussion centers on the physics problem of a mass m dropped through a tunnel drilled from the Earth's surface to its center. The key equations derived include the potential energy (PE) at the surface, given by PE = -GMm/R, and the kinetic energy (KE) relationship, leading to the velocity formula v = √(2GM/R). A discrepancy arises regarding the potential energy at the Earth's center, which is stated as -(3/2)(GMm/R) in a textbook. The correct approach involves recognizing that the mass M contributing to gravitational force varies with distance r from the center, necessitating the use of a constant mass density assumption for accurate calculations.

PREREQUISITES
  • Understanding of gravitational potential energy (PE) and kinetic energy (KE) principles.
  • Familiarity with Newton's law of universal gravitation.
  • Knowledge of calculus for deriving mass distributions within spherical bodies.
  • Concept of constant mass density in physics.
NEXT STEPS
  • Study the derivation of gravitational potential energy in varying mass distributions.
  • Learn about the implications of constant density assumptions in gravitational problems.
  • Explore the concept of gravitational force inside a spherical shell.
  • Investigate the applications of energy conservation in mechanics problems.
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Students of physics, particularly those studying mechanics and gravitational theory, as well as educators seeking to clarify concepts related to gravitational potential energy and kinetic energy in spherical bodies.

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Homework Statement



A tunnel is drilled from the surface of the earth(mass assumed to be M and radius to be R) to its center . A body of mass m is dropped from the surface to the center through the tunnel. What will be the velocity with which the body of mass m will hit the tunnel.

Homework Equations



Loss in PE = Gain In KE

Loss in PE = PE at surface - PE at center of earth.

= |-GMm/R - 0|

1/2 mv[2] = |-GMm/R|

v = √(2GM/R)

The Attempt at a Solution



But in a textbook , the PE at the center of Earth is given to be -(3/2) (GMm/R)

what is the right way of approaching the problem.
 
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The point where the potential energy is zero, is arbitrary. You assumed it to be the centre of the Earth which is not in agreement with problem's assumption. Of course you can solve the problem with your current assumption too.
 
Let's assume that ##R## is the radius of the planet, and ##r## is the distance between the body and the center.

Then the attractive force is not just ##F=-\frac{GMm}{r^2}##.
The value of ##M## that you should use varies with ##r##, since we're inside the planet.

The ##M## that contributes is the mass in the sub sphere that is still between you and the center of the planet. To calculate it, we need to assume for instance that the mass density is constant.

What would the mass ##M(r)## of the sub sphere of radius ##r## be?
 

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