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Ball suspended by a pulley: oscillation
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[QUOTE="inv4lid, post: 5982977, member: 636178"] [ATTACH=full]224427[/ATTACH] A ball of 100g, suspended from a pulley of a dynamometer, oscillates freely. The length of the pendulum thus obtained is 1m. What are the indications of the dynamometer when the ball is at the point A of it's trajectory? The maximum offset angle is 15 degrees. [h2]Homework Equations[/h2] α - alpha (angle), G - gravity, T - restoring force[/B] m= 0,1 kg. l = 1m. α = 15 degrees _________________| Sum of all forces (probably, not sure) [B]Attempts of solving: [/B] [I]If I'm not wrong, there are 2 components of acceleration: One that moves the object towards the equilibrium state mostly horizontally and one vertically. The normal component is vertical one, the tangential is horizontal. [/I] [B][I]G[SUB]t[/SUB] = ma[sub]t[/sub] Gsin α = ma[sub]t[/sub] sin 15 degrees = 0.26 a[sub]t[/sub] = 2,6 (m/s[sup]2[/sup]) G = mg = 1; G[sub]t[/sub] = 0,26 (N) (=ma[sub]t[/sub]) G[sub]N[/sub] = 0,74 (N)[/I][/B] [I][B]T-G[sub]N[/sub] = ma[sub]N[/sub] T - 0,74 = 0,1a[sub]N[/sub] [/B][/I] Any tips on how to get T or normal component of acceleration? [/QUOTE]
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Ball suspended by a pulley: oscillation
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