Ball thrown striaght up part C

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In summary, the problem is asking to find the maximum initial velocity (vmax) at which a ball can be thrown from the roof of a building in order for it to hit the ground at the same time as another ball that is dropped 1 second later. The height of the building is represented by h and the equations used are y=yo+vo*t+1/2*a*t^(2) for the height of each ball at time t. The statement to be solved is that both balls are on the ground at some time tg.
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Toranc3
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Homework Statement


A ball is thrown straight up from the edge of the roof of a building. A second ball is dropped from the roof 1 second later. You may ignore air resistance

If vo is greater than some value vmax, a value of h does not exist that allows both balls to hit the gorund at the same time. Solve for vmax.

Homework Equations



y=yo+vo*t+1/2*a*t^(2)

The Attempt at a Solution



I am not sure how to start it. Can somebody give me some hints?
 
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Presumably h is the height of the roof. Write down equations, one for each ball, for the height of the ball at time t. Make sure to use different variable names as appropriate (not making them both just 'y'). Using those equations, write the statement that each is on the ground at some time tg.
 

FAQ: Ball thrown striaght up part C

1. What is the maximum height reached by the ball in part C?

In part C, the maximum height reached by the ball is the same as the initial height at which the ball was thrown. This is because the ball reaches its highest point and then falls back down to the ground, following a parabolic path.

2. How long does it take for the ball to reach its maximum height in part C?

In part C, the ball reaches its maximum height at the halfway point of its trajectory. Therefore, the time taken for the ball to reach its maximum height is half of the total time taken for the ball to complete its journey.

3. Does the velocity of the ball change while it is in the air in part C?

Yes, the velocity of the ball changes while it is in the air in part C. Initially, the ball moves upwards with a positive velocity, then at the highest point it has a velocity of 0, and finally, it moves downwards with a negative velocity. This change in velocity is due to the acceleration of gravity.

4. How does air resistance affect the motion of the ball in part C?

In part C, air resistance (or drag) does not have a significant effect on the motion of the ball. This is because the ball is moving in a straight line and not at high speeds, so the force of air resistance is minimal. However, if the ball was thrown at a higher speed or at a different angle, air resistance would play a larger role in its motion.

5. What is the acceleration of the ball while it is in the air in part C?

The acceleration of the ball while it is in the air in part C is always equal to the acceleration due to gravity, which is approximately 9.8 m/s². This acceleration acts in the opposite direction to the velocity of the ball, causing it to slow down as it moves upwards and speed up as it moves downwards.

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