strangerep
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I wouldn't call it an axiom, but rather an application of projection operators, hence a special case.atyy said:My question is whether the filtering method of state preparation follows from the axioms in Chapters 2 (and 3), or whether it is an additional axiom.
By my reading, no. Instead, he has reinterpreted the 4th Cox axiom for probability (which is the same equation as (9.22)), i.e.,But for non-commuting R,S, are 9.28 and 9.29 then new axioms?
$$
\def\Pr{\text{Prob}}
\Pr(A\&B|C) ~=~ \Pr(A|C) \; \Pr(B|A\&C)
$$ into
$$\Pr(A\&B|C) ~:=~ \Pr(A|C) \; \Pr(B|A\&C) ~.$$
The only difference here is that I've changed "##=##" into "##:=##". In classical probability, both sides of the original equation make sense, but not so in QM for noncommuting quantities. Here, Ballentine generalizes the concept, though still restricted (iiuc) to the case of filtering-type operations.