Band discontinuities in semiconductor heterojunctions

In summary, a heterojunction formed between two semiconductor materials with different bandgaps, work functions, electron affinities and dielectric constants will have a discontinuity in the conduction and valence bands due to the difference in Fermi levels. This results in band bending and a transfer of electrons from the N-type to the p-type material. However, in a homojunction, the Fermi levels of the n- and p-type materials do not line up, resulting in net current flow and a depletion region. Chuang's book may provide more insight into this concept.
  • #1
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Two semiconductor materials have different bandgaps, different work functions, electron affinities and dielectric constants. Let's assume they are lattice matched. The larger bandgap material is doped n-type (or N-type) and the smaller doped p-type.

In the heterojunction formed epitaxially between the materials there is a discontinuity in the conduction band and a discontinuity in the valence band. This is attributed to the absolute value of the Fermi level in the bulk N-type material being higher than that of the p-type. So a number of electrons must transfer from N to p to equalise the Fermi levels of the two sides and this net charge flow across the interface causes band bending - up for the positive space-charge region in the N-type and down for the negative space-charge region in the p-type. So far so good.

I am struggling to reconcile this with the fact that there is band bending but no discontinuity in a homojunction. The Fermi levels of the n- and p-type homojunction material do not line up because they are above and below the intrinsic Fermi level, respectively, so we get net current flow, a depletion region, etc.

I have been back and forth between four textbooks looking for satisfaction. Can anybody enlighten me?

Thanks.
 
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  • #3
Great, thanks!
 

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