Basic Harmonic Frequencies Question

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SUMMARY

The discussion centers on determining the lowest resonant frequency and wave speed of a string fixed at 82.0 m, with observed resonant frequencies of 334.000 Hz and 389.667 Hz. The lowest resonant frequency, also known as the fundamental frequency, is calculated as 334.000 Hz. The wave speed of the string can be derived using the relationship between frequency and wavelength, leading to a calculated wave speed of 27.4 m/s.

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Homework Statement



A string is stretched between fixed supports separated by 82.0 m. It is observed to have resonant frequencies of 334.000 and 389.667 Hz, and no other resonant frequencies between these two.

A)What is the lowest resonant frequency of the string?

B)What is the wave speed of this string?


The Attempt at a Solution



I guess I don't really understand this question, Isn't 334 Hz the lowest frequency?
 
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Call the fundamental frequency F, then the higher harmonics of the string will have frequencies 2*F, 3*F, 4*F, ...

What you know is m*F = 334.000 Hz, and (m+1)*F = 389.667 Hz

(m+1)*F - m*F = ?
 

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