Why Does Calculating Train Engine Power Result in Different Values?

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Calculating the maximum power of a train engine traveling at 50 meters per second with a resistance of 30 kilonewtons yields a result of 1.5 megawatts, while the answer book states 1.47 megawatts. The discrepancy arises from the misunderstanding of how to apply force and power calculations, as force and power are different units and should not be subtracted directly. Gravity does not affect the horizontal motion of a level train, and the calculation involving gravity is incorrect. The book's answer may stem from an error or modification in the problem statement that was not properly verified. Overall, the discussion emphasizes the importance of accurate problem interpretation in physics calculations.
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Hi. I'm new and am trying to solve a simple question 'Find the max power of a train engine traveling level at 50 metres per second if total resistance to motion is 30 KiloNewtons.

I get power = force times velocity so 30000 x 50 = 1500000 = 1.5 Mega Watts. My answer book says 1.47 Mega Watts. I can see how 1.5MW minus 30KW = 1500000 - 30000 = 1.47MW. Also I can see that power times gravity of 9.8 = 1.5 MW times 9.8 N gives the same answer.

I can't see how you should subtract the force from the sum of the force and the distance, or how vertical gravity can reduce the speed of a horizontally moving train. Thanks :)
 
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Your math seems fine. Subtracting 30KW doesn't make sense since 30KW hasn't been computed anywhere, making it a random number. Subtracting the force doesn't make sense since force and power are different units and cannot be added. And yes, gravity plays no role since the problem says 'level'. Also 1.5MW * 9.8 m/sec² results in 14.7 mega-something, not 1.47 mega-something.

I cannot explain the book answer.
 
I think these book/web errors often arise when someone modifies the question and fails to check the answer given elsewhere.
That 9.8 produces the right leading digits is suggestive. The original might have been something like "a train of mass 30,000 kg and rolling resistance (or "rolling friction" or whatever) of 0.1..."
 
Thanks guys, massively appreciated :)
Interesting insight haruspex..
 
Thread 'Chain falling out of a horizontal tube onto a table'
My attempt: Initial total M.E = PE of hanging part + PE of part of chain in the tube. I've considered the table as to be at zero of PE. PE of hanging part = ##\frac{1}{2} \frac{m}{l}gh^{2}##. PE of part in the tube = ##\frac{m}{l}(l - h)gh##. Final ME = ##\frac{1}{2}\frac{m}{l}gh^{2}## + ##\frac{1}{2}\frac{m}{l}hv^{2}##. Since Initial ME = Final ME. Therefore, ##\frac{1}{2}\frac{m}{l}hv^{2}## = ##\frac{m}{l}(l-h)gh##. Solving this gives: ## v = \sqrt{2g(l-h)}##. But the answer in the book...

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