Basic log question, completely lost! :( 1. The problem statement, all variables and given/known data Prove that y = a(1+b)^t is equivalent to ln y = a+bt 2. Relevant equations 3. The attempt at a solution i'm really confused with how they could possibly be equal. y = a(1+b)^t t = ln y/ln a(1+b) ln y = t x ln (a+b) ln y = ln (a+b)^t Could someone please help.