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Basic Nuclear Fusion question on Binding energy

  1. Aug 30, 2012 #1
    Hey guys, I'm getting a bit confused about nuclear fusion. I understand the basics of binding energy being the energy required to split the nucleons apart etc. and the fact that in nuclear fusion you are combining two particles e.g. (2 deuterium nuclei) with a lowish binding energy to form a particle (he-4 or something) with a higher binding energy. I'm just getting a bit confused at why a higher binding energy means that the mass of the particle relative to the masses of the 2 fusion reactants is lower? Can someone here help explain it?

    I know nuclei with higher binding energy per nucleon have a lower*atomic weight*per nucleon, but I'm kind of confused at why?
     
  2. jcsd
  3. Aug 30, 2012 #2

    mfb

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    Binding energy is always negative (otherwise the state is not bound), and "high" is usually meant as absolute value. So helium has a "high negative" binding energy, it is actually a low-energetic state. This means that fusion can release energy while forming this state.
     
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