Nothing wrong with that. Taking "east" to the right and "south" downward, draw a line to the right with length "65 mph" and, at the end of that, draw a line downward with length "260 mph". That gives you a right triangle with legs of length 65 and 260. The airspeed is the length of hypotenuse. The Pythagorean theorem gives you that. Which angle you use depends on how you want to write the course. If you want to write it as a compass reading in degrees from north, it will be 90 plus the angle in the upper left of the triangle, where you started. If you want to write it as "degrees east of south", it will be 90 degrees minus that angle. In either case you can use the tangent function to find "that angle".Homework Statement
A pilot wants his groundspeed to be 260mph on a bearing of 180 degrees. An east wind is blowing at 65mph. What should his airspeed and heading be so that the wind will blow him back onto his intended course?
Homework Equations
The Attempt at a Solution
I drew it out, but apparently its wrong. I drew a right triangle with the wind as the horizontal and 260mph as the vertical and thats all i got. Please explain with concept too. Thanks