Bat Echolocation - Can Bats Locate Prey in the Dark?

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Discussion Overview

The discussion revolves around the concept of bat echolocation, specifically focusing on whether bats can locate prey in the dark using sound waves. The scope includes theoretical calculations related to the speed of sound in air and the wavelength of sound emitted by bats.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant presents a homework problem involving the calculation of the wavelength of an 80.0 kHz sound wave emitted by a bat, emphasizing the need for the wavelength to be equal to or less than the length of the prey (a moth).
  • Another participant suggests steps to find the speed of sound in air and the frequency, indicating that the speed of sound at 20 degrees Celsius is approximately 343 m/s.
  • A participant calculates the speed of sound at 10 degrees Celsius to be 338.28 m/s using the ideal gas law and questions the correctness of their calculation.
  • There is a caution about ensuring unit consistency in calculations, particularly converting values to meters and seconds.
  • A participant seeks clarification on how to convert their calculated frequency value into the appropriate units for speed.

Areas of Agreement / Disagreement

Participants generally agree on the need for unit consistency and the importance of calculating the speed of sound accurately, but there is no consensus on the correctness of the calculations presented, as participants are still working through the problem.

Contextual Notes

Limitations include potential inaccuracies in the speed of sound calculations due to temperature variations and the need for precise unit conversions, which have not been fully resolved in the discussion.

Who May Find This Useful

Students studying physics or related fields, particularly those interested in sound propagation, echolocation, and mathematical problem-solving in a homework context.

sphouxay
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Homework Statement



Bats are mainly active at night. They have several senses that they use to find their way about, locate prey, avoid obstacles, and "see" in the dark. Besides the usual sense of vision, bats are able to emit high-frequency sound waves and hear the echo that bounces back when these sound waves hit an object. This sonar-like system is called echolocation. Typical frequencies emitted by bats are between 20 and 200 kHz. Note that the human ear is sensitive only to frequencies as high as 20 kHz
A moth of length 1.0 cm is flying about 1.0 m from a bat when the bat emits a sound wave at 80.0 khz . The temperature of air is about 10.0 celsius. To sense the presence of the moth using echolocation, the bat must emit a sound with a wavelength equal to or less than the length of the insect.

The speed of sound that propagates in an ideal gas is given by

velocity = squareroot of(( (gamma = 1.4)*RT)/M



where gamma is the ratio of heat capacities (gamma = 1.4 for air), T is the absolute temperature in kelvins (which is equal to the Celsius temperature plus 273.15), M is the molar mass of the gas (for air, the average molar mass is 28.8 *10^-3 kg/mol), and R is the universal gas constant (R=8.314 j*mol^-1*K^-1).


Find the wavelength of the 80.0-khz wave emitted by the bat

Will the bat be able to locate the moth despite the darkness of the night?



Homework Equations



Wavelength = velocity/frequency

velocity = squareroot of(( (gamma = 1.4)*RT)/M






The Attempt at a Solution



Ill get back with my attempts as of now I am very flustered.
 
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Step 1, just find the speed of sound in air (hint look up the approx answer to check)
Step 2, find the frequency (check your units)
 
the speed of sound in air at 20 degree celsiusis is 343 m/s, my calculation with the ideal gas law is 338.28 is that correct? And for the frequency wouldn't I just have to divide the velocity of 338.28 by 80 khz. Is that even close 4.2285
 
Yes - except you want it at 10c.
The speed of sound is one of those numbers you shoudl have a rough idea of just so you can check your answer.

Be careful with the units in your answer, make sure everythign is in m and s-1
 
I did use 10 degree celsius which would be 273 + 10 (Conversion from celsius to kelvins) and I received 338.28. If my final answer is 4.2285 what am I converting that to to get my m and s^-1
 

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