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Battery’s terminal potential difference

  1. Jul 4, 2016 #1
    1. The problem statement, all variables and given/known data
    An external circuit with a total series resistance of 50 (omega) is connected to a 1.5 V AA battery which has an internal resistance of 1 (omega). What is the battery’s terminal potential difference?

    2. Relevant equations
    I = EMF / (R + r)


    3. The attempt at a solution
    I = EMF / (R + r) = 1.5V/ 51 Ohm = 29.412 mA

    V = 1.5V - 0.029412A * 1 Ohm = 1.47 Volt


    but i m still confused if i did it right or wrong please help

    Thank you!
     
  2. jcsd
  3. Jul 4, 2016 #2
    Its right
     
  4. Jul 5, 2016 #3

    CWatters

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