An external circuit with a total series resistance of 50 (omega) is connected to a 1.5 V AA battery which has an internal resistance of 1 (omega). What is the battery’s terminal potential difference?
I = EMF / (R + r)
The Attempt at a Solution
I = EMF / (R + r) = 1.5V/ 51 Ohm = 29.412 mA
V = 1.5V - 0.029412A * 1 Ohm = 1.47 Volt
but i m still confused if i did it right or wrong please help