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## Homework Statement

An external circuit with a total series resistance of 50 (omega) is connected to a 1.5 V AA battery which has an internal resistance of 1 (omega). What is the battery’s terminal potential difference?

## Homework Equations

I = EMF / (R + r)

## The Attempt at a Solution

I = EMF / (R + r) = 1.5V/ 51 Ohm = 29.412 mA

V = 1.5V - 0.029412A * 1 Ohm = 1.47 Volt

but i m still confused if i did it right or wrong please help

Thank you!