Battery’s terminal potential difference

[zohaibtarar]

Homework Statement

An external circuit with a total series resistance of 50 (omega) is connected to a 1.5 V AA battery which has an internal resistance of 1 (omega). What is the battery’s terminal potential difference?

Homework Equations

I = EMF / (R + r)

The Attempt at a Solution

I = EMF / (R + r) = 1.5V/ 51 Ohm = 29.412 mA

V = 1.5V - 0.029412A * 1 Ohm = 1.47 Voltbut i m still confused if i did it right or wrong please help

Thank you!

 

[Joyal Babu]

Its right

 

[CWatters]

+1.

The method used is fine. You can also solve it using the "potential divider rule"...

https://en.wikipedia.org/wiki/Voltage_divider