Bearing Stress of Hollow Tube w/ Pin & Force

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SUMMARY

The discussion focuses on calculating the bearing stress of a hollow tube with a pin and a force applied to the innermost tube. When a 36,000-pound load is applied, the bearing stress on each of the four holes is determined to be 18,000 pounds per square unit, calculated using the formula bearing stress = F/(2 * t_d), where F is the total load, t is the wall thickness, and d is the hole diameter. The initial assumption of dividing the load by four was incorrect; the correct approach considers the load distribution across two reaction points, leading to a bearing stress of 18,000 pounds per hole.

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  • Understanding of bearing stress calculations
  • Knowledge of hollow tube mechanics
  • Familiarity with load distribution principles
  • Basic concepts of structural engineering
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  • Research "Bearing Stress in Hollow Tubes" for detailed calculations
  • Study "Load Distribution in Structural Beams" to understand reaction forces
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  • Investigate "Finite Element Analysis (FEA) for Tube Structures" for advanced modeling techniques
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This discussion is beneficial for structural engineers, mechanical engineers, and students studying mechanics who are involved in the design and analysis of tubular structures under load.

gomerpyle
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For a hollow tube inside a hollow tube, with a pin passing through both and a force pushing down on the innermost tube, what would the bearing stress be on the holes (assuming tube wall thickness is equal)? Would the equivalent reaction force be F/4 since the pin is passing through 4 holes? So for example, say this is a jack stand with a 36,000 pound load on it. Would the bearing stress for each hole then be, 36,000/4 = 9000. Then bearing stress = F/td ? 9000/td Where t is wall thickness of tube and d is hole diameter?
 
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No - it's F/2 for each hole .

Think of the pin as a simple beam with two applied loads and two reaction loads .
 
Pin Loads.jpg
 
Last edited:

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