Calculating Stress Area at Hole Edge of Tube & Rod

  • Thread starter Thread starter pmlapl
  • Start date Start date
  • Tags Tags
    Area Edge Hole
Click For Summary
SUMMARY

This discussion focuses on calculating the stress area at the edge of a tube when a rod is inserted and secured by a pin. The key factors include axial tensile stress, bearing stress, and shear tearout at the hole. The bearing stress is calculated as the force on the wall at the pin divided by the product of the pin diameter and the wall thickness. The complexity of actual stress distribution is acknowledged, but a simplified analysis is recommended for design purposes.

PREREQUISITES
  • Understanding of axial tensile stress in structural engineering
  • Knowledge of bearing stress calculations
  • Familiarity with shear tearout concepts
  • Basic principles of force distribution in mechanical systems
NEXT STEPS
  • Research methods for calculating axial tensile stress in tubes
  • Study bearing stress formulas and applications in engineering
  • Learn about shear tearout analysis in mechanical design
  • Explore advanced stress distribution models for complex geometries
USEFUL FOR

Mechanical engineers, structural analysts, and anyone involved in the design and analysis of tube and rod assemblies under load conditions.

pmlapl
Messages
6
Reaction score
0
I have a tube with a rod inserted into it at a set depth. The rod is held in place by a round pin that passes through a hole in the side of the tube and into the rod. Assuming the pin and hole are the same diameter or very close, I'd like to know how to calculate the stress area on the edge of the tube when a force is applied to the end of the rod when the tube is anchored. I know that the force exerted by the pin is highest along the axis of the force and zero normal to it. So the force involved is not equal over the diameter of the pin which I'm puzzled about. Thanks for the help.
 
Engineering news on Phys.org
Actual stress distribution is quite complex, but for purposes of design, analysis can be simplified. In addition to axial tensile stress, a function of the tube cross section area, there are bearing stresses on the wall at the pin, which is the force
on the wall at the pin divided by ( pin diameter *wall thickness). Also check shear tearout at the hole. Assumption is that pin diameter is small relative to tube diameter.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
10
Views
3K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 8 ·
Replies
8
Views
19K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 31 ·
2
Replies
31
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 14 ·
Replies
14
Views
28K