Hello,(adsbygoogle = window.adsbygoogle || []).push({});

I just started taking a Modern Physics course in University, and have a moderate understanding of time dilation. The problem is that I'm stuck with a problem I asked myself.

I understand the light clock thought experiment.

If you are within a rocket ship moving at a fast speed and a light pulse come from the floor vertically, hits the ceiling and returns to the floor, it take [tex]\Delta[/tex]t= [tex]\frac{2h}{c}[/tex], where h is the height of the ship.

For someone observing from Earth, the light does not move in a straight line but in a triangle, and it would take instead [tex]\Delta[/tex]t = ([tex]\frac{2h}{c}[/tex]) / [tex]\sqrt{1-(v^2/c^2)}[/tex]which is the time dilation formula.

My question was what would happen if the experiment was conducted on Earth? Within the reference frame of the Earth-dweller, [tex]\Delta[/tex]t= [tex]\frac{2h}{c}[/tex], and inside the reference frame of the moving rocket, [tex]\Delta[/tex]t =([tex]\frac{2h}{c}[/tex]) / [tex]\sqrt{1-(v^2/c^2)}[/tex] Does this mean that now instead of time moving slower in the rocket, does it move faster? I know it can't just move faster just because I decided to do the experiment somewhere else, but I'm still confused.

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Beginner's questions on time dilation

**Physics Forums | Science Articles, Homework Help, Discussion**