Bending Stress in Top of T-Beam

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SUMMARY

The discussion focuses on calculating the maximum bending stress in a T-beam made of steel with a modulus of elasticity (E) of 200 GPa. The initial calculation yielded a bending stress of 2.573 GPa, which was deemed incorrect due to unit discrepancies. After adjusting the moment of inertia (I) and the centroid distance (C), the corrected bending stress was determined to be 88.29 MPa. The beam is supported at the center, and the load is applied eccentrically, necessitating careful consideration of moments in both the x and y directions.

PREREQUISITES
  • Understanding of bending stress calculations in beams
  • Familiarity with the moment of inertia formula I = BH^3/12
  • Knowledge of material properties, specifically steel's allowable stress
  • Basic principles of mechanics of materials
NEXT STEPS
  • Review the calculation of bending stress using the formula MC/I
  • Study the effects of eccentric loading on beam stress
  • Learn about the significance of moment of inertia in beam design
  • Investigate the allowable stress limits for different steel grades
USEFUL FOR

Structural engineers, mechanical engineers, and students studying mechanics of materials will benefit from this discussion, particularly those involved in beam design and analysis.

tsslaporte
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Homework Statement



T-Beam is Steel with E=200GPa

Find Max bending stress MC/I (right side where no glue)[/B]
MxcOwAK.png

80KG Load at Point "A" shown on the Top view

Blue stuff is glue, the right side has no Glue, so its just empty space

2. The attempt at a solution

I = BH^3/12 , where B = 0.04m H = 0.004
So I = 2.13 * 10^-10 m^4
C = 0.029m
M = 784.8 N * 0.024m = 18.8352 n-m

Solving that out I get 2.573 GPa which seems too high as steel can only see in MPa of stress.

So I'm not sure if the number I got is correct or I did something wrong with my calculation.
 
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MxcOwAK.png


The Beam is Supported in the center.

The Bending is happening not on the axis I assumed, the force is not in the center so

I = 0.08* 0.004^2 and C = 0.002

Now I get 88.29 MPa
 
tsslaporte said:
MxcOwAK.png


The Beam is Supported in the center.

The Bending is happening not on the axis I assumed, the force is not in the center so

I = 0.08* 0.004^2 and C = 0.002

Now I get 88.29 MPa

It's not clear what you are trying to do here. What is this point load and why is it applied to the flange of the beam?

Your expression for I seems to be incorrect, or at least it is unfamiliar to me. Have you checked to make sure the units make sense?

Your calculated bending stress values lack meaning if you don't know what stress the beam material is capable of withstanding without permanent deformation.
 
SteamKing said:
It's not clear what you are trying to do here. What is this point load and why is it applied to the flange of the beam?

Your expression for I seems to be incorrect, or at least it is unfamiliar to me. Have you checked to make sure the units make sense?

Your calculated bending stress values lack meaning if you don't know what stress the beam material is capable of withstanding without permanent deformation.

Hey,

The Beam is rigidly held in place except for the right side, so can assume a simple beam,(Square/rectangle) so I= BH^3/12 is correct.

I actually am still wrong, there is a moment in the y and x, I need to add them to find total bending stress.
 
tsslaporte said:
Hey,

The Beam is rigidly held in place except for the right side, so can assume a simple beam,(Square/rectangle) so I= BH^3/12 is correct.

I actually am still wrong, there is a moment in the y and x, I need to add them to find total bending stress.
I don't think I'd worry too much about the eccentric 'point' load a few mm off center in the y direction . I'd do it as you had in your original post after correcting the 'c' distance to .002m and checking your steel allowable stress for the material being used, as SteamKing noted .
 

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