Bernoulli's Principle density and velocity

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SUMMARY

The discussion centers on applying Bernoulli's Principle to calculate the pressure difference between two points in a fluid flow scenario. Given a fluid density of 1600 kg/m³ and velocities of 4 m/s at point A and 8 m/s at point B, the correct calculation yields a pressure difference of -7.7 x 10^4 Pa. The user initially calculated -3.84 x 10^4 Pa, but upon review, confirmed the answer key was incorrect, affirming their solution as accurate.

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Homework Statement




The density of the liquid flowing through a horizontal pipe is 1600 kg/m3. The speed of the fluid at point A is 4 m/s while at point B it is 8.0 m/s. What is the difference in pressure, PB - PA, between points B and A?



a. -1.9 x 10^3Pa

b. -3.8 x 10^4Pa

c. +4.5 x 10^4Pa

d. +5.0 x 10^4Pa

*e. -7.7 x 10^4Pa

Homework Equations



Pa+1/2*ρ*va2=Pb+1/2*ρ*vb2

The Attempt at a Solution


Pb-Pa=1/2*ρ*va2-1/2*ρ*vb2
Pb-Pa=1/2*ρ*(va2-vb2)
Pb-Pa=1/2*1600kg/m3*(4m/s2-8m/s2)
Pb-Pa=-3.84x104Pa

and the answer key says its -7.7 x 10^4Pa
what did I do wrong? :s
 
Physics news on Phys.org
The answer in the book is incorrect. You have the correct answer.
 
Thanks :)
 

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