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Bernoulli's Principle density and velocity

  1. Nov 22, 2011 #1
    1. The problem statement, all variables and given/known data


    The density of the liquid flowing through a horizontal pipe is 1600 kg/m3. The speed of the fluid at point A is 4 m/s while at point B it is 8.0 m/s. What is the difference in pressure, PB - PA, between points B and A?



    a. -1.9 x 10^3Pa

    b. -3.8 x 10^4Pa

    c. +4.5 x 10^4Pa

    d. +5.0 x 10^4Pa

    *e. -7.7 x 10^4Pa

    2. Relevant equations

    Pa+1/2*ρ*va2=Pb+1/2*ρ*vb2

    3. The attempt at a solution
    Pb-Pa=1/2*ρ*va2-1/2*ρ*vb2
    Pb-Pa=1/2*ρ*(va2-vb2)
    Pb-Pa=1/2*1600kg/m3*(4m/s2-8m/s2)
    Pb-Pa=-3.84x104Pa

    and the answer key says its -7.7 x 10^4Pa
    what did I do wrong? :s
     
  2. jcsd
  3. Nov 22, 2011 #2
    The answer in the book is incorrect. You have the correct answer.
     
  4. Nov 22, 2011 #3
    Thanks :)
     
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