- #1
Adel Makram
- 635
- 15
I think that both methods (1 and 2) of Bertrand Paradox may be equivalent if the probability is represented by area of the circle enclosed by each method rather than by distances.
Please see the attached file.
In both methods, the probability is approximately 0.6.
Please see the attached file.
In both methods, the probability is approximately 0.6.