Bessel's Equation and substitutions

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Homework Statement


Find a general solution in terms Jv of and Yv . Indicate
whether you could also J-v use instead of Yv. Use the
indicated substitution. Show the details of your work.

9x2y''+9xy'+(36x4-16)y=0

Substitution (z=x2)

Homework Equations



All given in part 1.

The Attempt at a Solution



Given z=x2, [itex]\frac{dz}{dx}[/itex]=2x
Therefore [itex]\frac{dy}{dx}[/itex]=[itex]\frac{dy}{dz}[/itex]*[itex]\frac{dz}{dx}[/itex]=2x*[itex]\frac{dy}{dz}[/itex]

But I need the second derivative of y with respect to x to make the substitution, this is where I run into trouble. Using the chain rule, I get this:
[itex]\frac{d^{2}y}{dx^{2}}[/itex]=2*[itex]\frac{dy}{dz}[/itex]+[itex]\frac{d}{dx}[/itex]([itex]\frac{dy}{dz}[/itex])*2x

I have no clue how to compute [itex]\frac{d}{dx}[/itex]([itex]\frac{dy}{dz}[/itex])
Any help would be appreciated.
 
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For any function [itex]\phi[/itex], [itex]\frac{d\phi}{dx}= \frac{d\phi}{dz}\frac{dz}{dx}[/itex]. In particular, if [itex]\phi= \frac{dy}{dz}[/itex] then [itex]\frac{d}{dx}\left(\frac{dy}{dz}\right)= \frac{d^2y}{dz^2}\left(\frac{dz}{dx}\right)[/itex]
 
i am also struggling with how I am going to compute