- #1
ILikeMath
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Homework Statement
[tex]81x^{2}y'' + 27xy' + (9x^{\frac{2}{3}}+8)y = 0 [/tex]
Hint: y = x1/3u
x1/3 = z
2. The attempt at a solution
Change of variables gives:
[tex] \frac{d^{2}y}{dx^{2}} = x^{\frac{1}{3}}\frac{d^{2}u}{dx^{2}}+\frac{2}{3}x^{-\frac{2}{3}}\frac{du}{dx} - \frac{2}{9}x^{-\frac{5}{3}}u [/tex]
Plugging into original equation:
[tex]81x^{\frac{7}{3}}u'' + 81x^{\frac{4}{3}}u'+(9x-x^{\frac{1}{3}})u = 0[/tex]
Then using x1/3 = z, z' = 1/3 x-2/3
[tex]\frac{d^{2}u}{dx^{2}} = -\frac{2}{9}x^{-\frac{5}{3}}\frac{du}{dz}+\frac{1}{3}x^{-\frac{2}{3}}\frac{d^{2}u}{dz^{2}}[/tex]
Plugging in:
[tex]3z^{4}u'' + zu' + (z^{2} - \frac{1}{9})u = 0 [/tex]
The Bessel equation does not have a coeffcient in front of the first term and it is also of the second order:
x2y'' + xy' + (x2 - n2)y = 0
Can anyone help me get my equation into the Bessel equation form please?