Bessel's Integrals with Cosine or Sine?

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SUMMARY

Bessel's integrals can be defined using different notations, as illustrated by the two expressions provided by the participants. The standard definition is given by $$J_n(x) = \frac {1} {2\pi} \int_{-\pi}^{\pi} e^{i(xsin(\theta) - n\theta)} \, d\theta$$, while the professor's version is $$J_m(Z) = \frac {1} {2\pi} \int_{-\pi}^{\pi} e^{i(Zcos(\theta))} e^{(- im\theta)} \, d\theta$$. Despite the apparent differences, both expressions represent the same mathematical concept, as cosine and sine functions can be interchanged due to their orthogonality. To prove their equivalence, one can apply a variable substitution, such as setting a new variable equal to theta + π/2.

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Bessel's integral form: is it e to the power of a cosine or sine?
Hello all,

This is knowledge needed to solve my take-home final exam but I just want to ask about the definition of Bessel's integrals. This is not a problem on the exam. Wikipedia says the integral is defined as:

$$J_n(x) = \frac {1} {2\pi} \int_{-\pi}^{\pi} e^{i(xsin(\theta) - n\theta)} \, d\theta$$

My professor wrote it as:

$$J_m(Z) = \frac {1} {2\pi} \int_{-\pi}^{\pi} e^{i(Zcos(\theta))} e^{(- im\theta)} \, d\theta$$

Ignoring notation differences and I understand that cosine and sine form an orthogonal basis and are essentially the same as they can be easily expressed in terms of each other, but how do I justify that these two expressions are EXACTLY the same without any modifications with negative signs and such?

Thanks!

Jesse
 
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I don't think they have the same constants. To see this, try defining a new variable equal to theta+pi/2, and evaluating the integral.
 
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