Beta decay problems, not getting the right answer

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SUMMARY

This discussion focuses on the calculations related to beta decay problems involving phosphorus-32, boron-12, and nitrogen-12 isotopes. The correct energy values for the emitted neutrinos and electrons were identified as 0.25 MeV, 12.8 MeV, and 5.8 MeV, respectively. The user initially calculated incorrect neutrino energies due to misapplication of mass-energy conversion principles. A detailed step-by-step solution is requested to clarify the calculations and correct methodology.

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crosbykins
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Homework Statement



a) What is the energy of the neutrino, if a phosphorus-32 atom (31.97390
u) beta-decays into a sulphur-32 atom (31.97207 u), and the kinetic energy of the
accompanying electron is 0.90 MeV? (answer: 0.25 MeV)

b) A boron-12 atom (12.01435 u) beta-decays into a carbon-12 atom (12.00000 u).
What is the maximum kinetic energy of the emitted electron? (answer: 12.8 MeV)

c) In the β+ decay of nitrogen-12 (12.01864 u) into carbon-12 (12.00000 u), a
positron with energy of 11.0 MeV is emitted. What is the energy of the electron
neutrino? (answer: 5.8 MeV)



Homework Equations



** equations not really used

The Attempt at a Solution



a)

Δ m = 31.97390u – 31.97207u
= 1.83*10^-3 u

(1.83*10^-3 u) (931 MeV)
= 1.70 MeV

1.70 MeV – 0.90MeV
=.80 MeV

Therefore, the energy of the neutrino is .80 MeV.

b)
Δ m = 12.01435u – 12.00000u
= .01435u

(.01435u)( 931 MeV)
=13 MeV

Therefore, the maximum kinetic energy is 13 MeV.

c)

Δ m = 12.01864u - 12.00000u
= .01864u

(.01864u) ( 931 MeV)
=17 MeV

17 MeV – 11.0MeV
= 7MeV

Therefore, the energy of the neutrino is 7MeV.

***right, so the answers i got are all wrong, i think the method in which I'm doing this is wrong, but i can't find information in my book on how to do it the correct way... a step-by-step solution would really really be appreaciated, thanks :)
 
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