# Bifurcation Diagram <Diff. Eqns>

1. Dec 11, 2007

### dalarev

1. The problem statement, all variables and given/known data

Draw the bifurcation diagram for the following equation.

:attached:

2. Relevant equations

I believe this is a population D.E.

3. The attempt at a solution

I'm ashamed to say I'm at a complete loss with this problem. The only step I'm familiar with is finding the critical points, which would be p=0 and p=4 in this case. My professor gave is this problem and told us to study it for a final tomorrow. Help would be GREATLY appreciated.

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2. Dec 12, 2007

### HallsofIvy

Staff Emeritus
Your differential equation is dP/dt= P(4-P)- h. (Why make a gif and attach it for something that easy to type?) No, you did not find the critical points (more correctly "equilbrium solutions" since those are constant functions that satisfy the equation) . Equillibrium solutions are such that dP/dt= P(4-P)-h= 0. They would be P(t)= 0 and P(t)= 4 only if h were equal to 0. As it is, you have the quadratic equation $P^2- 4P+ h= 0$ so the equilibrium solutions depend upon h. You can use the quadratic formula to write them. You will note that for some values of h, there is no (real) solution. For some values of h, there are two distinct solutions and for precisely one value of h, there is a single solution.

The "bifurcation diagram" is a graph with h on the horizontal axis, the equilibrium values of P on the vertical axis. For this problem that should be a parabola lieing on it's side: precisely the graph of h= P(4-P).