Biholomorphic Mapping: Proving f(z) = z for All z in Ω?

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SUMMARY

The discussion centers on proving that a biholomorphic mapping f(z) = z for all z in Ω, given that f(a) = a and f'(a) = 1 for some a in Ω. The Riemann Mapping Theorem is referenced, indicating that every simply connected proper open set in the plane is equivalent to the unit disk. The Schwarz Lemma is highlighted as a key tool, demonstrating that the only biholomorphic mappings from the unit disk to itself take the form φ(z) = ζ (z - a) / (overline{a}z - 1), where |ζ| = 1 and a is within the unit disk.

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Suppose f is a biholomorphic mapping from Ω to Ω, if f(a) = a and f'(a) = 1 for some a in Ω, can we prove that f(z) = z for all z in Ω?
 
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look at the corresponding result for the unit disc, then look at the riemann mapping theorem that says every simply connected proper open set in the plane is equivalent to the disc. (i don't know the answer.)
 
Schwarz lemma ( http://en.wikipedia.org/wiki/Schwarz_lemma ) can be used to prove that the only biholomorphic mappings from the unit disk to itself have the form

[itex]\varphi(z)=\zeta \frac{z-a}{\overline{a}z-1}[/itex]

with [itex]|\zeta|=1[/itex] and a in the unit disk. Use this.
 

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