- #1

laurabon

- 17

- 0

My first idea was to set z=1/x

and in this case z→0

Thus I can expand f(z)= arctan(1/z) near 0

so I obtain 1/z-1/3(z^3)

Then I try to reverse the substitution but this is incorrect .I discovered after that arctanx=π/2−arctan(1/x) for all x>0 and than I can write the correct result walphram alpha gives to me

Now I would like to know if there is an alternative way to get the result without knowing arctanx=π/2−arctan(1/x) for all x>0