Binding energy calculation of a nucleus

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SUMMARY

The discussion focuses on calculating the binding energy of the isotope 11B (Boron-11) using the mass-energy equivalence principle. The user correctly identifies the mass of protons and neutrons, calculates the unbound system mass, and derives the binding energy using the equation E=mc². However, the final binding energy value of 4.44E28 MeV is significantly higher than expected, indicating a miscalculation. The user is advised to convert atomic mass units (amu) to kilograms before calculating energy in joules and subsequently converting to MeV.

PREREQUISITES
  • Understanding of binding energy and its significance in nuclear physics
  • Familiarity with mass-energy equivalence (E=mc²)
  • Knowledge of atomic mass units (amu) and their conversion to kilograms
  • Basic principles of nuclear forces, particularly the strong nuclear force
NEXT STEPS
  • Learn about the conversion of atomic mass units to kilograms for accurate energy calculations
  • Research standard binding energy values for isotopes to compare results
  • Study the strong nuclear force and its implications on binding energy
  • Explore advanced nuclear physics concepts, such as nuclear stability and decay
USEFUL FOR

Students and enthusiasts in nuclear physics, particularly those studying isotopes and binding energy calculations, as well as educators seeking to clarify concepts related to nuclear forces and energy transformations.

ellynx
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Hello,

I'd appreciate feedback on my calculation of binding energy, just wanted to check if I'm on the right track w/ regards to calculation steps (and thought process).

I'll try to be as clear as possible, please give me input if there's some notations / steps I should correct and keep in mind I have limited knowledge on the subject.


Homework Statement


Basically I want to calculate the binding energy per nucleus of the isotope 11B in MeV.

Binding energy of the nucleus, which is the energy keeping the protons and neutrons together, thus the energy needed to break apart the "bonds" between the p+'s and n0's.
(in terms of force notation, would this be the strong nuclear force?)


Data given:

11B: m = 11,0093 amu (Z = 5) (Z = # of p+ (I assume, since the # of p+ relates to the "iso" part of isotope))


mass/proton = 1,007276 amu
mass/neutron = 1,008665 amu


Homework Equations



∆m = (sum of protons and neutrons) - (measured mass of the isotope)

E=mC2

binding energy = ∆m·C2

The Attempt at a Solution



11B ∑m = 5p+ * 1,007275 amu + 6n0 * 1,008665 amu = 11,08837 amu (the unbound system calculated mass)

11B m = 11,0093 amu (measured somehow)


∆m = 11,08837 - 11,0093 = 0,07907 amu

Binding energy = 0,07907 amu * (3E8 m/s)^2 = 7,1163E15 J ( is it safe to say this is joules kg·m^2/s^2 ?) or do I need to convert amu's into Kg's first?

Assuming I get the result in J I continue to convert into MeV:

1 J = 6,24E18 eV = 6,24E12 MeV

MeV: 7,1163E15*J * 6,24E12 MeV/J = 4,44E28 MeV

This seems to me like a LOT of energy, how can I best evaluate my answer? Does this amount of energy seem like a reasonable amount? Can I relate it to the strong nuclear force?

Thanks.
 
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I looked up some binding energy values, and they all lay in quite a different interval. That value I got has to be horrendously off course.

Maybe I should divide by the atom number, but then again I would still get a pretty crazy value.
 
I think you're more likely to get a response to this in the physics sections for homework questions (don't ask me where!). I don't think you can post the same question twice though, you may like to ask a moderator to transfer it, perhaps.
 
ellynx said:
do I need to convert amu's into Kg's first?

Yes.

--
 

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