Solving Binding Energy Problem of 147N

[archa1c]

Homework Statement

Problem: Calculate the binding energy of ¹⁴₇N (nuclear mass of 13.999234 amu) in Joules per nucleon. According to periodic table, the mass of N is 14.0067 amu.

Homework Equations

E = mc²

The Attempt at a Solution

Calculate mass defect:

13.999234 - 14.0067 = 0.007466
Convert to kg:

0.007466 * (1.66053886 * 10^-27) = 1.23976 * 10^-29

Use mass/energy equivalence (E = mc²) to calculate energy of the mass defect:

E = (1.23976 * 10^-29)(3 * 10⁸)² = 1.115784 * 10^-12[/EQ]

The result *should* be the binding energy of the entire molecule (I would have thought per nucleon would be just dividing this by 14) - but the answer my book gives is 1.19773*10^-12 J/nucleon.

Where have I gone wrong?

 

[Borek]

Periodic table doesn't contain mass of a nuclide in question.

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