Solving Binding Energy Problem of 147N

  • #1
archa1c
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Homework Statement



Problem: Calculate the binding energy of 147N (nuclear mass of 13.999234 amu) in Joules per nucleon. According to periodic table, the mass of N is 14.0067 amu.

Homework Equations


E = mc2


The Attempt at a Solution



Calculate mass defect:

13.999234 - 14.0067 = 0.007466
Convert to kg:

0.007466 * (1.66053886 * 10-27) = 1.23976 * 10-29

Use mass/energy equivalence (E = mc2) to calculate energy of the mass defect:

E = (1.23976 * 10-29)(3 * 108)2 = 1.115784 * 10-12[/EQ]

The result *should* be the binding energy of the entire molecule (I would have thought per nucleon would be just dividing this by 14) - but the answer my book gives is 1.19773*10-12 J/nucleon.

Where have I gone wrong?
 
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  • #2
Periodic table doesn't contain mass of a nuclide in question.

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