- #1

leminn

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- Homework Statement
- I'm trying to calculate the binding energy in MeV per nucleon of the nucleus for Sulphur-34. However, I am told that my calculation is wrong and that the mass of the electrons do not have to be taken into account.

- Relevant Equations
- Binding Energy per nucleon of the nucleus in MeV

How exactly would it then be calculated? Here's what I have tried:

proton mass: 1.007276 amu

Neutron mass: 1.008665 amu

Sulphur-34 mass: 33.9678668 amu

Calculation:

1.##(16\cdot1.007276)+(18\cdot1.008665)+(16 \cdot0.000549)=34.28117##

2.##34.28117-33.9678668=0.3133032##

3. 1 atomic mass unit = ##\frac{931.5 \mathrm{MeV}}{c^2}##

4. ##[E=mc^2]=0.3133032 ×\frac{931.5 MeV}{c^2} =291.840051 (\text{total})##

##\frac{291.840051}{34}=8.583530912\mathrm{MeV}## (per nucleon)

I would really appreciate the communities support on finding my error.

proton mass: 1.007276 amu

Neutron mass: 1.008665 amu

Sulphur-34 mass: 33.9678668 amu

Calculation:

1.##(16\cdot1.007276)+(18\cdot1.008665)+(16 \cdot0.000549)=34.28117##

2.##34.28117-33.9678668=0.3133032##

3. 1 atomic mass unit = ##\frac{931.5 \mathrm{MeV}}{c^2}##

4. ##[E=mc^2]=0.3133032 ×\frac{931.5 MeV}{c^2} =291.840051 (\text{total})##

##\frac{291.840051}{34}=8.583530912\mathrm{MeV}## (per nucleon)

I would really appreciate the communities support on finding my error.

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