# Binding energy of an electron in an excited state?

SundaeRider

## Homework Statement

How much energy is required to remove an electron from a hydrogen atom in a state with n = 8?

## Homework Equations

E = - (1 / 4pi*epsilon_0)(me^4/2(h-bar)^2)(1/n^2)

Where E is the total energy of the electron.

## The Attempt at a Solution

I know that if you solve the above equation for the ground state (n = 1), the binding energy of the electron is equal to E, but I'm not so sure about excited states. Do I merely solve the above equation for n = 8, or is there something I'm missing?

thebigstar25
as you have said , to remove an electron from a hydrogen atom which is in a ground state , the least amount of energy you have to give is 13.6ev (note that En= -13.6/n^2) and n=1 in the ground state ...

so when the atom is at n=8, what is the least amount of energy you have to give it in order to remove the electron (can you see some kind of symmetry here ) ... :)

SundaeRider
as you have said , to remove an electron from a hydrogen atom which is in a ground state , the least amount of energy you have to give is 13.6ev (note that En= -13.6/n^2) and n=1 in the ground state ...

so when the atom is at n=8, what is the least amount of energy you have to give it in order to remove the electron (can you see some kind of symmetry here ) ... :)

Well, the answer I got is 0.2124 eV...